\documentclass[12pt]{article}
\usepackage{amsmath, amssymb, graphicx, array, fancyhdr, unicode-math, multirow}

\DeclareMathOperator{\Var}{Var}
\DeclareMathOperator{\sd}{SD}
\DeclareMathOperator{\Pois}{Pois}
\DeclareMathOperator{\Bin}{Bin}
\DeclareMathOperator{\NegBin}{NegBin}
\DeclareMathOperator{\sech}{sech}


% Text: Calibri, all bold
\setmainfont{Calibri}
\renewcommand{\seriesdefault}{b}

% Math: choose a math font and visually embolden it
\setmathfont{TeX Gyre Termes Math}                  % base math font
\setmathfont[FakeBold=1.9]{TeX Gyre Termes Math}    % embolden; adjust 1.6–2.4

% header
\pagestyle{fancy}
\fancyhf{}
\lhead{\resizebox{!}{2cm}{K}}
\chead{\raisebox{0.5cm}{\Huge Independant Events}} % (add title text if you want)
\rhead{\resizebox{!}{2cm}{K}}
\setlength{\headheight}{2.5cm}
\setlength{\headsep}{12pt} % space between header and body

\begin{document}
\thispagestyle{fancy}

% -------- PAGE 1 --------
\begin{table}[h!]
  \renewcommand{\arraystretch}{1.2}

% -------- Single -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{5}{*}{\fbox{\includegraphics[width=1in]{images/single.png}}} 
& $P(A) = 0.40$\\
& $P(B) = 0.70$\\
&$\raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/MutuallyIndependant.png}}(A,B) = \mathrel{\raisebox{-0.2\height}{\includegraphics[width=0.25in]{images/thumb_up.png}}}$\\
&\\
&\\
\end{tabular}

% -------- Abstract -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{5}{*}{\fbox{\includegraphics[width=1in]{images/abstract.png}}} 
&$ \raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/MutuallyIndependant.png}}(A,B) \rightarrow P(A|B) = P(A)$ \\
&\hrule\\
&\\
&$ \raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/MutuallyIndependant.png}}(A,B) \rightarrow P(A \cap B) = P(A) \times  P(B) $\\
&\hrule\\
&\\
&$ \raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/MutuallyIndependant.png}}(A,B) \rightarrow P(A \cup B) = P(A) + P(B) - P(A) \times  P(B)$\\
&$ \raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/MutuallyIndependant.png}}(A,B) \rightarrow P(A \cup B) = 0.40 + 0.70 - 0.40 \times  0.70$\\
&$ \raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/MutuallyIndependant.png}}(A,B) \rightarrow P(A \cup B) = 0.82$\\
&\\
\end{tabular}

% -------- Question -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{5}{*}{\fbox{\includegraphics[width=1in]{images/question.png}}} 
&$P(E) = 0.84$\\
&$P(F) = 0.65$\\
&$\raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/MutuallyIndependant.png}}(E,F) = \mathrel{\raisebox{-0.2\height}{\includegraphics[width=0.25in]{images/thumb_up.png}}}$\\
&$(E \cap F^c) \cup (E^c \cap F) = ?$\\
\end{tabular}
\end{table}

% second page
\newpage
\thispagestyle{fancy}
\begin{table}[h!]
% -------- Answer -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{5}{*}{\fbox{\includegraphics[width=1in]{images/key.png}}} 
&$P(F^c) = 1 - P(F) = 1 - 0.65 = 0.35$\\
&$P(E^c) = 1 - P(E) = 1 - 0.84 = 0.16$\\
&\hrule\\
&\\
&$P(E \cap F^c) = P(E) \cdot P(F^c) = 0.84 \times 0.35 = 0.294$\\
&$P(E^c \cap F) = P(E^c) \cdot P(F) = 0.16 \times 0.65 = 0.104$\\
&\hrule\\
&\\
&$(E \cap F^c) \cup (E^c \cap F) = 0.294 + 0.104 = 0.398$\\
\end{tabular}
\end{table}
 

\end{document}