\documentclass[12pt]{article}
\usepackage{amsmath, amssymb, graphicx, array, fancyhdr, unicode-math, multirow}

\DeclareMathOperator{\Var}{Var}
\DeclareMathOperator{\sd}{SD}
\DeclareMathOperator{\Pois}{Pois}
\DeclareMathOperator{\Bin}{Bin}
\DeclareMathOperator{\NegBin}{NegBin}
\DeclareMathOperator{\sech}{sech}


% Text: Calibri, all bold
\setmainfont{Calibri}
\renewcommand{\seriesdefault}{b}

% Math: choose a math font and visually embolden it
\setmathfont{TeX Gyre Termes Math}                  % base math font
\setmathfont[FakeBold=1.9]{TeX Gyre Termes Math}    % embolden; adjust 1.6–2.4

% header
\pagestyle{fancy}
\fancyhf{}
\lhead{\resizebox{!}{2cm}{C}}
\chead{\raisebox{0.5cm}{\Huge Odds and Probability}} % (add title text if you want)
\rhead{\resizebox{!}{2cm}{C}}
\setlength{\headheight}{2.5cm}
\setlength{\headsep}{12pt} % space between header and body

\begin{document}
\thispagestyle{fancy}

% -------- PAGE 1 --------
\begin{table}[h!]
  \renewcommand{\arraystretch}{1.2}

% -------- Single -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{5}{*}{\fbox{\includegraphics[width=1in]{images/single.png}}} 
&$S=\{1,2,3,4\}$\\
&$T=\{1\}$\\
&\\
&\\
&\\
&\\
\end{tabular}

% -------- Abstract -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{5}{*}{\fbox{\includegraphics[width=1in]{images/abstract.png}}} 
&$P(T) = \frac {|T|}{|S|} = \frac {1}{4} = 0.25$\\
&$P(T^C) = 1 - P(T) = 0.75$\\
&\hrule\\
&\\
&$ \frac{|T|}{|T^C|} = \frac {|E|}{|S|} \times \frac {|S|}{|E^C|} = \frac {P(E)}{P(E^C)} = \frac {P(E)}{1-P(E)}$\\
&\hrule\\
&\\
&$ a:b \rightarrow \frac {a}{a+b} = \frac {ak} {ak + bk} = \frac {|E|}{|E| + |E^C|} = \frac {|E|}{|S|} = P(E)$\\
&\\
&\\
\end{tabular}

% -------- Question -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{5}{*}{\fbox{\includegraphics[width=1in]{images/question.png}}} 
&$A = \{H,T\}$\\
&$B = \raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/Pull.png}}(A,3) = \{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT\} \rightarrow |B| = 8$\\
&$C = \{HHT, HTH, THH, HHH\} \rightarrow |C| = 4$\\
&$a:b(C) = ?$\\
&\\
\end{tabular}
\end{table}




% second page
\newpage
\thispagestyle{fancy}
\begin{table}[h!]
% -------- Answer -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{5}{*}{\fbox{\includegraphics[width=1in]{images/key.png}}} 
&$A = \{H,T\}$\\
&$B = \raisebox{-1.0ex}{\includegraphics[width=0.25in]{images/Pull.png}}(A,3) = \{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT\} \rightarrow |B| = 8$\\
&$C = \{HHT, HTH, THH, HHH\} \rightarrow |C| = 4$\\
&$a:b(C) =\frac {|B| - |C|}{|C|} = \frac {8-4}{4} = 4:4 = 1:1$\\
&\\
\end{tabular}
\end{table}

\end{document}