\documentclass[12pt]{article}
\usepackage{amsmath, amssymb, graphicx, array, fancyhdr, unicode-math, multirow}

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\DeclareMathOperator{\Pois}{Pois}
\DeclareMathOperator{\Bin}{Bin}
\DeclareMathOperator{\NegBin}{NegBin}
\DeclareMathOperator{\sech}{sech}


% Text: Calibri, all bold
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% Math: choose a math font and visually embolden it
\setmathfont{TeX Gyre Termes Math}                  % base math font
\setmathfont[FakeBold=1.9]{TeX Gyre Termes Math}    % embolden; adjust 1.6–2.4

% header
\pagestyle{fancy}
\fancyhf{}
\renewcommand{\headrulewidth}{0pt}   % <-- removes first line

\lhead{\resizebox{!}{1.5cm}{A}} 
\chead{%
  \raisebox{0.2cm}{%
    \shortstack{\Huge Survival Distribution \\ \Huge Function }%
  }%
}
\rhead{\resizebox{!}{1.5cm}{A}}

\setlength{\headheight}{1cm}
\setlength{\headsep}{12pt}

\begin{document}
\par\noindent\rule{\linewidth}{1.2pt}\par
\thispagestyle{fancy}

% -------- PAGE 1 --------
\begin{table}[h!]
  \renewcommand{\arraystretch}{1.2}

% -------- Single -------------------
\begin{tabular}{m{1.2in} m{4in}}
\multirow{4}{*}{\fbox{\includegraphics[width=1in]{images/single.png}}} 
&$S(x)=P(X>x)$\\
&$P(x<0)=1$\\
&$P(0\le x\le 10)=1-\dfrac{x}{10}$\\
&$P(x>10) = 0$\\
\end{tabular}
\par\noindent\rule{\linewidth}{1.2pt}\par
% -------- Abstract -------------------
\begin{tabular}{m{1.2in} m{4in}}
\\
\multirow{4}{*}{\fbox{\includegraphics[width=1in]{images/abstract.png}}} 
&$F(x)=1-S(x)$\\
&$F(x<0)=0$\\
&$F(0\le x \le 10)=x/10$\\
&$F(x>10)=1$\\
&\hrule\\
&\\
&$P(3<X\le 7)=F(7)-F(3)=\frac{7}{10}-\frac{3}{10}=\boxed{0.4}$\\
&\hrule\\
&\\
&$P(3<X\le 7)=S(3)-S(7)=\left(1-\frac{3}{10}\right)-\left(1-\frac{7}{10}\right)=\boxed{0.4}$\\
&\\
\end{tabular}
\par\noindent\rule{\linewidth}{1.2pt}\par
% -------- Question -------------------
\begin{tabular}{m{1.2in} m{4in}}
\\
\multirow{4}{*}{\fbox{\includegraphics[width=1in]{images/question.png}}} 
&$S(x<0) = 1$\\
&$S(0\le x \le 100) = 1/10(100-x)^{1/2}$\\
&$S(x>100) = 0$\\
&$CDF=?$\\
&\\
&\\
&\\
\end{tabular}
\end{table}


% second page
\newpage
\thispagestyle{fancy}
\par\noindent\rule{\linewidth}{1.2pt}\par
\begin{table}[h!]
% -------- Answer -------------------
\begin{tabular}{m{1.2in} m{4in}}
\\
\multirow{4}{*}{\fbox{\includegraphics[width=1in]{images/key.png}}} 
&$F(x<0)=1 - S(x<0)$\\ 
&$F(x<0)= 1 - P(x<0)$\\ 
&$F(x<0)= 1 - 1$\\
&$F(x<0)=0$\\
&\\
&$F( 0 \le x \le 100)=1 - S( 0 \le x \le 100)$\\ 
&$F( 0 \le x \le 100)= 1 - P(0 \le x \le 100)$\\
&$F( 0 \le x \le 100)= 1 - \dfrac{1}{10}\sqrt{\,100 - x\,}$\\
&\\
&$F(x>100)=1-S(x>100)$\\ 
&$F(x>100)= 1 - P(x>100)$\\ 
&$F(x>100)= 1 - 0$\\ 
&$F(x>100)= 1$\\
&\hrule\\
&\\
&$P(65 < X \le 75) = F(75) - F(65)$\\
&\\
&$F(75)=1 - \frac{1}{10}\sqrt{100 - 75}$\\
&$F(75)=1 - \frac{1}{10}\cdot5$\\
&$F(75)=1 - 0.5$\\
&$F(75)=0.5$\\
&\\
&$F(65)=1 - \frac{1}{10}\sqrt{100 - 65}$\\
&$F(65)=1 - \frac{\sqrt{35}}{10}$\\
&\\
&$P(65 < X \le 75)=0.5 - \Bigl(1 - \frac{\sqrt{35}}{10}\Bigr)$\\
&$P(65 < X \le 75)=\frac{\sqrt{35}-5}{10}$\\
&$P(65 < X \le 75)\approx\boxed{0.0916}$\\
\end{tabular}
\end{table}
\end{document}